IMC / 2001 / Problems / Day 2, P7
IMC 2001 · Day 2 · P7
very hardLet be integers and be real non-negative numbers such that Prove that each and each equals either 0 or 1.
Solution (official)
Multiply the left hand side polynomials. We obtain the following equalities: Among them one can find equations and From these equations it follows that . Taking into account that we can see that .
Now looking at the following equations we notice that all 's must be less than or equal to 1. The same statement holds for the 's. It follows from that one of the numbers equals 0 while the other one must be 1. Follow by induction.
How the field did
contestants scored
182
average (of 20)
4.67
solved (≥ 80%)
12.1%
near-0 (≤ 10%)
56.6%
discrimination
0.23
Score distribution (field cohort)
Computed on contestants with a meaningful total (field cohort); discrimination is the corrected item–total correlation.