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IMC / 2007 / Problems / Day 2, P7

IMC 2007 · Day 2 · P7

medium

Let f:RRf : \mathbb{R} \to \mathbb{R} be a continuous function. Suppose that for any c>0c > 0, the graph of ff can be moved to the graph of cfcf using only a translation or a rotation. Does this imply that f(x)=ax+bf(x) = ax + b for some real numbers aa and bb?

Solution (official)

No. The function f(x)=exf(x) = e^x also has this property since cex=ex+logcc e^x = e^{x + \log c}.

How the field did

contestants scored
242
average (of 20)
9.87
solved (≥ 80%)
48.8%
near-0 (≤ 10%)
50.0%
discrimination
0.44

Score distribution (field cohort)

Computed on contestants with a meaningful total (field cohort); discrimination is the corrected item–total correlation.

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