Unofficial archive — problems, solutions & results © IMC, reproduced with permission.

IMC / 2013 / Problems / Day 1, P1

IMC 2013 · Day 1 · P1

Let AA and BB be real symmetric matrices with all eigenvalues strictly greater than 1. Let λ\lambda be a real eigenvalue of matrix ABAB. Prove that λ>1|\lambda| > 1.

(Proposed by Pavel Kozhevnikov, MIPT, Moscow)

Solution (official)

The transforms given by AA and BB strictly increase the length of every nonzero vector, this can be seen easily in a basis where the matrix is diagonal with entries greater than 1 in the diagonal. Hence their product ABAB also strictly increases the length of any nonzero vector, and therefore its real eigenvalues are all greater than 1 or less than 1-1.

Similar problems