IMC / 2024 / Problems / Day 1, P5
IMC 2024 · Day 1 · P5
killerLet be positive integers. Choose independent, uniformly distributed random points in the unit ball centered at the origin. For a point denote by the probability that the convex hull of contains . Prove that if and the distance of from the origin is smaller than the distance of from the origin, then .
(proposed by Fedor Petrov, St Petersburg State University)
Solution (official)
By radial symmetry of the distribution, depends only on (the distance between and ), so, we may assume that lies on the segment between and . For points and denote by the indicator function of the event “ is in the convex hull of ”. The claim follows from the following deterministic inequality where are arbitrary points in general position and the summations are over all choices of signs (here is identified with the origin, that is, and are symmetric with respect to ). Indeed, taking the expectation in (1) over independent random uniform , we get . (To be specific, here “general position” means that for any point set , which does not contain simultaneosuly and , is not contained in an (affine) -dimensional plane. This holds with probability 1.)
To prove (1), we use the following formula for the characteristic function of the convex polyhedron : if are all facets of , and is the convex hull of and , then , where the sign is plus if and are on the same side of , and minus otherwise. Indeed, for every point in general position look how the ray intersects the boundary of and realize that for at most two summands the contribution of the RHS at point is non-zero, and the total contribution equals 1 when is inside and 0 (possibly as ) otherwise. Use this formula for every polyhedron with vertices , where each is . These polyhedrons are simplicial (all facets are simplices) because of the general position condition. Sum up over all such , we get the expression of as a linear combination of , where are simplices formed by and some points in (not containing and simultaneously).
For proving (1), it suffices to verify that all coefficients of in this linear combination are positive (since two sides of (1) are the values of the sum at and ). Let's find a coefficient of , where, say, is a simplex with vertices . The plane through partitions onto two parts (containing ) and (not containing ). For every pair with , either both points belong to , or one belongs to and another to . goes with the plus sign for with vertices and other vertices from , and with the minus sign for with vertices and other vertices from . It is immediate that there are at least as many pluses as minuses.
How the field did
Score distribution (field cohort)
Computed on contestants with a meaningful total (field cohort); discrimination is the corrected item–total correlation.