IMC / 2008 / Problems / Day 2, P8
IMC 2008 · Day 2 · P8
hardTwo different ellipses are given. One focus of the first ellipse coincides with one focus of the second ellipse. Prove that the ellipses have at most two points in common.
Solution (official)
It is well known that an ellipse might be defined by a focus (a point) and a directrix (a straight line), as a locus of points such that the distance to the focus divided by the distance to the directrix is equal to a given number . So, if a point belongs to both ellipses with the same focus and directrices , , then (here we denote by , distances between the corresponding line and the point ). The equation defines two lines, whose equations are linear combinations with coefficients of the normalized equations of lines but of those two only one is relevant, since and should lie on the same side of each directrix. So, we have that all possible points lie on one line. The intersection of a line and an ellipse consists of at most two points.
How the field did
Score distribution (field cohort)
Computed on contestants with a meaningful total (field cohort); discrimination is the corrected item–total correlation.